MinAbsSum at app.codility.com/programmers in PHP Explained: Given array of integers, find the lowest absolute sum of elements.
Task score : 100% - Correctness : 100% ; Performance : 100%
Detected time complexity :
Lesson 17 at app.codility.com/programmers
The solution and its explanation are given below.
Category of Article : Technology | Computers and Software | Algorithm
By: Chrysanthus Date Published: 4 Oct 2025
Problem
For a given array A of N integers and a sequence S of N integers from the set {−1, 1}, we define val(A, S) as follows:
val(A, S) = |sum{ A[i]*S[i] for i = 0..N−1 }|
(Assume that the sum of zero elements equals zero.)
For a given array A, we are looking for such a sequence S that minimizes val(A,S).
Write a function:
function solution($A);
that, given an array A of N integers, computes the minimum value of val(A,S) from all possible values of val(A,S) for all possible sequences S of N integers from the set {−1, 1}.
For example, given array:
A[0] = 1
A[1] = 5
A[2] = 2
A[3] = -2
your function should return 0, since for S = [−1, 1, −1, 1], val(A, S) = 0, which is the minimum possible value.
Write an efficient algorithm for the following assumptions:
· N is an integer within the range [0..20,000];
· each element of array A is an integer within the range [−100..100].
Note
| . . . | means take the positive value of what is inside.
In order to better understand the problem, three different sets of S are used for illustration, as follows:
A = [1, 5, 2, -2] and S = [-1, +1, -1, +1]
val(A, S) = |sum{ A[i]*S[i] for i = 0..N−1 }| = |1x(-1) + 5x(+1) + 2x(-1) + (-2)x(+1)|
= |(-1) + (+5) + (-2) + (-2)| = |-1 + 5 – 2 – 2| = |0| = 0 .
Note that the given set for S = [-1, +1, -1, +1] is just one of 2N sets; other two sets of which are as follows:
A = [1, 5, 2, -2] and S = [1, 1, 1, 1]
val(A, S) = |sum{ A[i]*S[i] for i = 0..N−1 }| = |1x1 + 5x1 + 2x1 + -2x1| = |1 + 5 + 2 – 2| = |+6| = 6
A = [1, 5, 2, -2] and S = [-1, -1, +1, -1]
val(A, S) = |sum{ A[i]*S[i] for i = 0..N−1 }| = |1x-1 + 5x-1 + 2x+1 + -2x-1| = |-1 + -5 + +2 ++ 2| = |-1 - 5 + 2 + 2| = |-2| = 2 .
The three answers here are 0, 6 and 2 and the minimum is 0. Zero does not necessarily have to be the minimum for other similar problems (tasks). The minimum can still be any number higher than 0 (for other problems).
In the problem description, it is said, “(Assume that the sum of zero elements equals zero.)”. So when N is 0 for an empty set, val(A, S) = 0.
Problem Interpretation
Using the given example, the question is, what is the minimum absolute sum of a given set of numbers, with all the different possible combinations of negative and positive signs, for the numbers. From above, the given set is the A = [1, 5, 2, -2]. Now {−1, 1, −1, 1} is one set of positive and negative signs. {1, 1, 1, 1} is another set of positive (and negative signs/zero-negative). {−1, -1, −1, -1} is yet another set of (positive and) negative signs.
If the set of signs is {−1, 1, −1, 1}, then the absolute minimum sum is |-1 + 5 – 2 – 2| = |0| = 0. If the set of signs is {1, 1, 1, 1}, then the absolute minimum sum is |1 + 5 + 2 – 2| = |+6| = 6. If the set of signs is {-1, -1, 1, -1}, then the absolute minimum sum is |-1 - 5 + 2 + 2| = |-2| = 2.
Illustration
The given example is used for illustration. Let the + sign of +1 be represented by the bit (Binary Digit) of 1. Let the negative sign of -1 be represented by the bit (Binary Digit) of 0. So the set {−1, 1, −1, 1} becomes the binary number 0101 which is the decimal number 510. The set {1, 1, 1, 1}} is the binary number 1111 which is the decimal number 1510. The set {-1, -1, 1, -1} is the binary number 0010 which is the decimal number 210.
So the different decimal values for k are 0, 1, 2, 3, 4, 5, 5, 6, 7, 8, 10, 11, 12, 13, 14, 15. In binary, these numbers are: 0000, 0001, 0010, 0011, 0100, 0101, 0110, 0111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, with each considered from the right end. If there are N elements in the given set, then there are N (or N+1 which includes the empty set) sets, consisting of 1’s and/or 0’s – see table below. Remember that each value for k represents a sub-task. The different possible sub-task results, are actually from the different combinations of k and the indexes from 0 to N. Each combination has a result. dp stands for dynamic programming.
So, 010 means - , considered as - - - -. 110 means + , considered as - - - +. 210 means +,- , considered as - - + -. 310 means +,+ , considered as - - + +. 410 means +,-,- considered as - + - -. 810 means +,-,-,- , considered as + - - -; and so on.
Different Examples
Well, the following tables show the results for different sets:
The given set is {1, 5, 2, -2}.
|
Index |
signs |
set |
summing |
sum |
abs(sum) |
|||
|
0 |
-1 |
-1 |
-1 |
-1 |
1, 5, 2, -2 |
-1-5-2+2 |
-6 |
6 |
|
1 |
-1 |
-1 |
-1 |
+1 |
1, 5, 2, -2 |
-1-5-2-2 |
-10 |
10 |
|
2 |
-1 |
-1 |
+1 |
-1 |
1, 5, 2, -2 |
-1-5+2+2 |
-2 |
2 |
|
3 |
-1 |
-1 |
+1 |
+1 |
1, 5, 2, -2 |
-1-5+2-2 |
-6 |
6 |
|
4 |
-1 |
+1 |
-1 |
-1 |
1, 5, 2, -2 |
-1+5-2+2 |
+4 |
4 |
|
5 |
-1 |
+1 |
-1 |
+1 |
1, 5, 2, -2 |
-1+5-2-2 |
+0 |
0 |
|
6 |
-1 |
+1 |
+1 |
-1 |
1, 5, 2, -2 |
-1+5+2+2 |
+8 |
8 |
|
7 |
-1 |
+1 |
+1 |
+1 |
1, 5, 2, -2 |
-1+5+2-2 |
+4 |
4 |
|
8 |
+1 |
-1 |
-1 |
-1 |
1, 5, 2, -2 |
+1-5-2+2 |
-4 |
4 |
|
9 |
+1 |
-1 |
-1 |
+1 |
1, 5, 2, -2 |
+1-5-2-2 |
-8 |
8 |
|
10 |
+1 |
-1 |
+1 |
-1 |
1, 5, 2, -2 |
+1-5+2+2 |
-0 |
0 |
|
11 |
+1 |
-1 |
+1 |
+1 |
1, 5, 2, -2 |
+1-5+2-2 |
-4 |
4 |
|
12 |
+1 |
+1 |
-1 |
-1 |
1, 5, 2, -2 |
+1+5-2+2 |
+6 |
6 |
|
13 |
+1 |
+1 |
-1 |
+1 |
1, 5, 2, -2 |
+1+5-2-2 |
+2 |
2 |
|
14 |
+1 |
+1 |
+1 |
-1 |
1, 5, 2, -2 |
+1+5+2+2 |
+10 |
10 |
|
15 |
+1 |
+1 |
+1 |
+1 |
1, 5, 2, -2 |
+1+5+2-2 |
+6 |
6 |
For the set {1, 5, 2, -2}, the minimum abs(sum) of 0 is obtained at index 5 with -1,+1,-1,+1 (0101) or at index 10 with +1,-1,+1,-1 (1010).
The given set is {1, -4, 2}.
|
Index |
Signs |
set |
summing |
sum |
abs(sum) |
||
|
0 |
-1 |
-1 |
-1 |
1, -4, 2 |
-1+4-2 |
+1 |
1 |
|
1 |
-1 |
-1 |
+1 |
1, -4, 2 |
-1+4+2 |
+5 |
5 |
|
2 |
-1 |
+1 |
-1 |
1, -4, 2 |
-1-4-2 |
-7 |
7 |
|
3 |
-1 |
+1 |
+1 |
1, -4, 2 |
-1-4+2 |
-3 |
3 |
|
4 |
+1 |
-1 |
-1 |
1, -4, 2 |
+1+4-2 |
+3 |
3 |
|
5 |
+1 |
-1 |
+1 |
1, -4, 2 |
+1+4+2 |
+7 |
7 |
|
6 |
+1 |
+1 |
-1 |
1, -4, 2 |
+1-4-2 |
-5 |
5 |
|
7 |
+1 |
+1 |
+1 |
1, -4, 2 |
+1-4+2 |
-1 |
1 |
For the set {1, -4, 2}, the minimum abs(sum) of 1 is obtained at index 0 with -1,-1,-1 (000) or at index 7 with +1,+1,+1 (111).
The given set is {2, -5}.
|
Index |
signs |
set |
summing |
sum |
abs(sum) |
|
|
0 |
-1 |
-1 |
2, -5 |
-2+5 |
+3 |
3 |
|
1 |
-1 |
+1 |
2, -5 |
-2-5 |
-7 |
7 |
|
2 |
+1 |
-1 |
2, -5 |
+2+5 |
+7 |
7 |
|
3 |
+1 |
+1 |
2, -5 |
+2-5 |
-3 |
3 |
For the set {2, -5}, the minimum abs(sum) of 3 is obtained at index 0 with -1,-1, (00) or at index 3 with +1,+1 (11).
The given set is {6}.
|
Index |
signs |
Set |
summing |
sum |
abs(sum) |
|
0 |
-1 |
6 |
-6 |
-6 |
6 |
|
1 |
+1 |
6 |
+6 |
+6 |
6 |
For the set {6}, the minimum abs(sum) of 6 is obtained at index 0 with -1 (0) or at index 1 with +1 (1).
The Program
In the code, conversion of the index k from base 10 to base 2 is used.
The pow() function for power is in the math library. So the math.h header has to be included. To evaluate 2N, do
ret = pow(2, N)
The abs() function for absolute, is in the cstdlib library. So the cstdlib header has to be included.
The assumptions in the program description are:
· N is an integer within the range [0..20,000];
· each element of array A is an integer within the range [−100..100].
So the minimum absolute sum cannot exceed 20000 * 100 + 1 = 2000001 (could still be 2000000)
The program is (read the comments as well):
<?php
function solution($A) {
$N = count($A);
$pw = pow(2,$N);
$minAbsSum = 20000 * 100 + 1;
if ($N==0) return 0;
//code for binary content
for ($k=0; $k < $pw; $k++) { //converting each number in the range K, to base 2 number
$no = $k; //as well as looking for minimum |sum{ A[i]*S[i] for i = 0..N−1 }|
$j = $N-1;
$sum = 0;
while ($j >= 0) { //the number bits
$remainder = $no % 2;
if ($remainder == 0)
$sum = $sum + (-1 * $A[$j]);
if ($remainder == 1)
$sum = $sum + (+1 * $A[$j]);
if ($j == 0)
break;
$no = (int)($no / 2); //integer division
$j--;
}
$sum = abs($sum);
if ($sum < $minAbsSum)
$minAbsSum = $sum;
}
return $minAbsSum;
}
$A = [1, 5, 2, -2];
$ret1 = solution($A);
echo $ret1 . "\n";
$B = [1, -4, 2];
$ret2 = solution($B);
echo $ret2 . "\n";
$C = [2, -5];
$ret3 = solution($C);
echo $ret3 . "\n";
$D = [6];
$ret4 = solution($D);
echo $ret4 . "\n";
$E = [10, 20, 30, 5];
$ret5 = solution($E);
echo $ret5 . "\n";
$F = [];
$ret6 = solution($F);
echo $ret6 . "\n";
?>
Output is:
1
3
6
5
0
At app.codility.com/programmers the scoring for this solution(), using the particular test cases at app.codility.com/programmers, is:
Task score : 54% - Correctness : 100% ; Performance : 0%
Analysis summary
Example tests
|
example1 |
✔ OK |
Correctness tests
|
simple1 |
✔ OK |
|
simple2 |
✔ OK |
|
simple3 |
✔ OK |
|
range |
✔ OK |
|
extreme |
✔ OK |
|
functional |
✔ OK |
Performance tests
|
medium1 1. 0.004 s WRONG ANSWER, got 2000001 expected 0 2. 0.003 s OK
|
✘ WRONG ANSWER
|
|
medium2 1. 0.004 s WRONG ANSWER, got 2000001 expected 5 2. 0.003 s OK
|
✘ WRONG ANSWER
|
|
big1 1. 0.004 s WRONG ANSWER, got 2000001 expected 2 2. 0.003 s OK
|
✘ WRONG ANSWER
|
|
big3 1. 0.004 s WRONG ANSWER, got 2000001 expected 3
|
✘ WRONG ANSWER
|
|
big4 1. 0.004 s WRONG ANSWER, got 2000001 expected10 2. 0.004 s OK
|
✘ WRONG ANSWER
|
Conclusion
The author believes that all the answers on performance by the examiner are wrong assessments, for the following reasons:
- No timing complaint has been made. In fact, the timings for some of them are OK.
- Take for example, the case of medium2. The examiner's expected answer is 5 (got 2000001) and the author's equivalent answer is also 5, for his program above.
- All the examiner's answers have "got 2000001". Does that make sense?
So the scoring for the author should have been:
Task score : 100% - Correctness : 100% ; Performance : 100%
Thanks for reading
The rest of the 17 lessons, with explanation of lessons, explanation of tasks, and explanation of solutions, can be found at (click): Explanations in PHP for the 17 Algorithm Lessons at https://app.codility.com/programmers with Problems and Solutions
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